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获取某个节点的流程处理人【查看:969 回复:0】

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admin 发表于：2017/8/17 16:05:28 楼主

var opts=$TOOLS.createOptions();
var userProcess = getUserProcess();
var doc = getCurrentDocument();
var domainid = getDomainid();
var nodeName="流程审批";  //流程节点名称
var sql="select id,actorid as item_actorid,name as item_name,'" + domainid + "' as domainid from T_ACTORHIS where NODEHIS_ID in (select ID from t_relationhis where docid='"+doc.getId()+"' and startnodename='"+nodeName+"')";
println(sql+"=====sql===");
var datas = queryBySQL(sql);
for (var it = datas.iterator(); it.hasNext();) {
   var d = it.next();
   var userid = d.getItemValueAsString("actorid");
   var username = d.getItemValueAsString("name");
   opts.add(username,userid);
}opts;

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